0=16x^2+162

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Solution for 0=16x^2+162 equation: 



0=16x^2+162

We move all terms to the left:

0-(16x^2+162)=0

We add all the numbers together, and all the variables

-(16x^2+162)=0

We get rid of parentheses

-16x^2-162=0

a = -16; b = 0; c = -162;
Δ = b2-4ac
Δ = 02-4·(-16)·(-162)
Δ = -10368
Delta is less than zero, so there is no solution for the equation

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